How many different numbers can be written with five digits?


Law Sa G See a fun puzzle about. Two numbers A and 15 Theirs Sa If G is 45, then what is the value of A? To solve this, we will first get 45 producers. The producers are 1,3, 5, 9, 15 and 45. It is clear that A can have several values. A = 45 if they are Sa G45 would be. But this is going to be because 45 numbers are divisible by 15. So we find out another value. It turns out 45 of the first four producers, excluding 9, are divided into three by nine, but not divisible by 9. So the value of A can be 9. 9th and 15th. Sa G = 45

Earlier we discussed a simple method to extract the square root of a large number. See another easy way. Let's assume the square root of 3364. First we will look, (60) 2 = 3600, which is larger than 3364. Again (50) 2 = 2,500, which is smaller than 3364. So the determining square root is between 50 and 60. Now since the last two digits of the square is 64, so the last digit of the square root must be 8, because (8) 2 = 64 So we can say the square root of 3364 is 58.
This week's puzzle
2 and 4, 6, that is, 6,6, 6, 6, how many different numbers can be written in these five digits?
If you think a little bit you will get the answer. Online comment form or quayum @ gmail. Please send reply to com.
Last week's puzzle answers
The puzzle was such that: What is the sum of the derivatives obtained by subtracting the numbers from the average value of a few numbers?
Answer:
Sum of the components is 0 (zero).
Almost everyone gave the correct answer. Thank you all.
How did you answer?
The average quality of the average quality is the total difference of the numbers from this value, the total difference in the number in the lower part is the same. That is, the sum of the reciprocals obtained by subtracting the numbers from the average value = 0 (zero). For example, the average of 2, 4, 6, 8 and 10 is 6 Now, by subtracting the numbers from 6, the pub is respectively (-4), (-2), (0), (2) and (4). The sum of these bits = (-6) + (+ 6) = 0 (zero)

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